A sphere is a perfectly round solid — every point on its surface is the same distance (the radius) from the center. Cutting a sphere exactly in half gives a hemisphere, with volume $\frac{1}{2}\cdot\frac{4}{3}\pi r^3=\frac{2}{3}\pi r^3$. Composite solids are real-world shapes built from simpler pieces: a grain silo might be a cylinder topped by a hemisphere, or a bullet is a cylinder with a cone tip. The key strategy is always to identify the component shapes, compute each volume separately, then add or subtract. A sphere's surface area is exactly 4 times the area of a great circle — a useful fact to remember.
★★★ Cone Removed from Cylinder (Ice Cream Problem)
An ice cream cup is a cylinder of radius 3 cm and height 8 cm with a conical bottom of the same radius and height 5 cm. Find the volume of ice cream the cup can hold.
The ice cream fills the cylindrical portion only. The conical bottom holds the stick/wafer, not ice cream. Actually — let me restate: find the total internal volume = cylinder + cone.
A solid sphere is inscribed in a cube of side length 10 cm. Find (a) the volume of the sphere and (b) the volume of space between the sphere and the cube walls.
A sphere inscribed in a cube touches all six faces. Its diameter equals the side length, so $r=5$ cm.
The sphere fills only $\approx52.4\%$ of the cube. Final answers: V (sphere) = 523.6 cm³, V (gap) = 476.4 cm³.
★★★ How Many Steel Balls Fit?
A cylindrical container with diameter 20 cm and height 30 cm is to be filled with solid steel balls each of diameter 4 cm. Assuming random packing at 64% efficiency, how many balls fit and what is their total volume?
Volume of one ball: $V_{\text{ball}}=\frac{4}{3}\pi(2)^3=\frac{32\pi}{3}=33.51\text{ cm}^3$.