Annuity Due
An annuity due has payments at the start of each period.
$$P=A\left(\frac{(1+i)^{n-1}-1}{(1+i)^{n-1}i}\right)+A$$
$$F=A\left(\frac{(1+i)^{n+1}-1}{i}\right)-A$$
An annuity due has payments at the start of each period.
An engineer receives P25,000 at the beginning of each year for 18 years. Find the present value at 4% compounded annually at the time of the first payment.
Final answer: P329,142.
A student receives P3,000 at the beginning of each 3 months for 4 years. Find the sum at the end of 4 years at 6% compounded quarterly.
Final answer: P54,604.