Conic Sections
Conic Sections β Definitions, Locus, and General Equation
General Second-Degree Equation of a Conic
Any conic section can be represented by the general quadratic equation:
$$ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 $$
The presence of the $Bxy$ term indicates a possible rotation of axes.
Circles, ellipses, parabolas, and hyperbolas can all appear rotated when $B \neq 0$.
How to Distinguish Conics Using A, B, and C
Ignoring rotation (or after rotating axes so that $B = 0$), the nature of the conic is determined by the signs of $A$ and $C$:
- Circle: $A = C$ and $B = 0$
- Ellipse: $A$ and $C$ have the same sign but not equal
- Parabola: either $A = 0$ or $C = 0$ (but not both)
- Hyperbola: $A$ and $C$ have opposite signs
With rotation included ($B \neq 0$), the classification is done using the discriminant:
$$ \Delta = B^2 - 4AC $$
- Ellipse: $\Delta < 0$ (includes circles)
- Parabola: $\Delta = 0$
- Hyperbola: $\Delta > 0$
Eccentricity of Conic Sections
The eccentricity of a conic section describes the shape and βflatnessβ of the curve.
It is defined as:
$$ e = \frac{\text{distance to focus}}{\text{distance to directrix}} $$
This value fully determines the nature of the conic:
- Circle: $e = 0$
- Ellipse: $0 < e < 1$
- Parabola: $e = 1$
- Hyperbola: $e > 1$
1. Eccentricity of an Ellipse
For the ellipse
$$ \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1, $$
the first eccentricity is:
$$ e = \frac{c}{a} \qquad \text{where } c^2 = a^2 - b^2 $$
The eccentricity describes flatness:
- $e = 0$: ellipse becomes a circle
- small $e$: round ellipse
- $e$ close to 1: very flat, elongated ellipse
2. Second Eccentricity of an Ellipse
An alternate measure of shape is the second eccentricity:
$$ e' = \frac{c}{b} $$
Using $c^2 = a^2 - b^2$, we may also write:
$$ e' = \sqrt{\frac{a^2}{b^2} - 1} $$
3. Distance From Center to the Directrix of an Ellipse
The directrices of the ellipse lie at the distance:
$$ d = \frac{a^2}{c} = \frac{a}{e} $$
measured horizontally from the center.
Derivation
Start with the eccentricity definition:
$$ e = \frac{c}{a}. $$
A point $P$ on the ellipse satisfies:
$$ \frac{\text{distance to focus}}{\text{distance to directrix}} = e. $$
Evaluating this at the vertex $(a,0)$ gives:
$$ \frac{a - c}{\frac{a^2}{c} - a} = \frac{c}{a}, $$
which simplifies to confirm the directrix location:
$$ x = \frac{a^2}{c}. $$
Thus:
$$ d = \frac{a^2}{c} = \frac{a}{e}. $$