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Types of Soil Classification

Common soil classification systems used in geotechnical work are the Textural Classification or USDA system, the AASHTO system, and the Unified Soil Classification System (USCS).

  1. USDA: based on corrected percentages of sand, silt, and clay.
  2. AASHTO: commonly used for highway subgrade materials.
  3. USCS: commonly used in geotechnical engineering and foundation work.

USDA Corrected Percentages

If a soil contains gravel or particles larger than 2 mm, correct the percentages of sand, silt, and clay based on the portion finer than 2 mm.

$$\% \text{ corrected component} = \frac{\% \text{ component}}{\% \text{ sand} + \% \text{ silt} + \% \text{ clay}}(100)$$

The corrected sand, silt, and clay percentages should add to 100 percent before using the USDA textural triangle.

AASHTO Classification Criteria

In AASHTO classification, gravel is the fraction passing the 25 mm sieve and retained on No. 10 sieve, sand is the fraction passing No. 10 and retained on No. 200, and silt-clay is the fraction passing No. 200.

$$F_{200} \le 35\% \Rightarrow \text{granular material}$$
$$F_{200} > 35\% \Rightarrow \text{silt-clay material}$$
$$PI \le 10 \Rightarrow \text{silty fine fraction}$$
$$PI \ge 11 \Rightarrow \text{clayey fine fraction}$$

AASHTO Group Index

The group index evaluates the quality of a soil as highway subgrade material. Negative values are reported as zero and final values are rounded to the nearest whole number.

$$GI = (F_{200}-35)[0.2+0.005(LL-40)] + 0.01(F_{200}-15)(PI-10)$$
$$GI_{LL} = (F_{200}-35)[0.2+0.005(LL-40)]$$
$$GI_{PI} = 0.01(F_{200}-15)(PI-10)$$

For A-1-a, A-1-b, A-2-4, A-2-5, and A-3 soils, the group index is always zero. For A-2-6 and A-2-7 soils, use the plasticity-index part only.

USCS Gradation Coefficients

The particle-size distribution curve is used to obtain effective size and gradation coefficients.

$$D_{10} = \text{effective size}$$
$$C_u = \frac{D_{60}}{D_{10}}$$
$$C_c = \frac{D_{30}^2}{D_{10}D_{60}}$$
$$S_o = \sqrt{\frac{D_{75}}{D_{25}}}$$

USCS Classification Procedure

Start with No. 200 sieve passing. If more than 50 percent passes No. 200, the soil is fine-grained. If less than 50 percent passes No. 200, the soil is coarse-grained.

$$F_{200} > 50\% \Rightarrow \text{fine-grained soil}$$
$$F_{200} < 50\% \Rightarrow \text{coarse-grained soil}$$
$$R_4 > 50\% \text{ of coarse fraction} \Rightarrow \text{gravel}$$
$$R_4 < 50\% \text{ of coarse fraction} \Rightarrow \text{sand}$$

For clean coarse-grained soils, use GW, GP, SW, or SP. With more than 12 percent fines, use GM, GC, SM, or SC. Between 5 and 12 percent fines, use a dual symbol.

Well-Graded Criteria and Plasticity Chart

Well-graded gravels and sands must satisfy both coefficient requirements. Fine-grained soils use liquid limit and the plasticity chart.

$$C_u > 4 \text{ for gravel}$$
$$C_u > 6 \text{ for sand}$$
$$1 < C_c < 3$$
$$PI = 0.73(LL - 20) \quad \text{A-line}$$
$$LL > 50\% \Rightarrow \text{high plasticity}$$
$$LL < 50\% \Rightarrow \text{low plasticity}$$

Problem: AASHTO Percent Gravel, Sand, and Fines

From a sieve analysis of a soil sample, 54 percent passes the No. 10 sieve and 4 percent passes the No. 200 sieve. Find the percentages of gravel, sand, and silt-clay under AASHTO.

$$\% \text{ gravel} = 100 - 54 = 46\%$$
$$\% \text{ sand} = 54 - 4 = 50\%$$
$$\% \text{ silt-clay} = F_{200} = 4\%$$

Answer: Gravel = 46 percent, sand = 50 percent, and fines = 4 percent.

Problem: Effective Size, Uniformity, and USCS

A soil sample has 4 percent passing No. 200 and is predominantly sand. From the grain-size curve, $D_{10}$ is about 0.15 mm and $D_{60}$ is about 2.2 mm. Classify the soil using USCS if $C_c = 1.28$.

$$D_{10} \approx 0.15 \text{ mm}$$
$$C_u = \frac{D_{60}}{D_{10}} = \frac{2.2}{0.15} = 14.67 \approx 15$$
$$1 < C_c = 1.28 < 3$$

Since $F_{200} = 4\%$, the soil is a clean coarse-grained soil. Since it is sand, $C_u > 6$, and $1 < C_c < 3$, it is well-graded sand.

Answer: SW, well-graded sand.

Problem: Coefficient of Gradation

For a soil sample, determine the coefficient of gradation from $D_{10}$, $D_{30}$, and $D_{60}$ obtained from the grain-size distribution curve.

$$C_c = \frac{D_{30}^2}{D_{10}D_{60}}$$

Read $D_{10}$, $D_{30}$, and $D_{60}$ at 10 percent, 30 percent, and 60 percent finer from the semi-log grain-size curve, then substitute directly into the formula.

Problem: Percentages from Sieve Curve

From a sieve curve: for soil A, 98 percent passes No. 4; for soil B, 95 percent passes No. 4 and 34 percent passes No. 200; for soil C, 12 percent passes No. 200. Determine gravel for A, sand for B, and silt-clay for C.

$$\% \text{ gravel for A} = 100 - 98 = 2\%$$
$$\% \text{ sand for B} = 95 - 34 = 61\%$$
$$\% \text{ silt-clay for C} = 12\%$$

Problem: AASHTO Soil A

Soil A has $F_{200} = 17\%$, liquid limit = 35 percent, and plastic limit = 20 percent. Classify it using AASHTO.

$$F_{200}=17\% < 35\% \Rightarrow \text{granular material}$$
$$PI = LL - PL = 35 - 20 = 15$$
$$GI = 0.01(17 - 15)(15 - 10) = 0.10 \approx 0$$

Answer: A-2-6 (0).

Problem: AASHTO Soil B

Soil B has $F_{200} = 33\%$, liquid limit = 46 percent, and plastic limit = 29 percent. Classify it using AASHTO.

$$F_{200}=33\% < 35\% \Rightarrow \text{granular material}$$
$$PI = 46 - 29 = 17$$
$$GI = 0.01(33 - 15)(17 - 10) = 1.26 \approx 1$$

Answer: A-2-7 (1).

Problem: AASHTO Soil C

Soil C has $F_{200} = 63\%$, liquid limit = 47 percent, and plastic limit = 24 percent. Classify it using AASHTO.

$$F_{200}=63\% > 35\% \Rightarrow \text{silt-clay material}$$
$$PI = 47 - 24 = 23$$
$$LL - 30 = 47 - 30 = 17$$
$$PI > LL - 30 \Rightarrow A\text{-}7\text{-}6$$
$$GI = (63 - 35)[0.2 + 0.005(47 - 40)] + 0.01(63 - 15)(23 - 10)$$
$$GI = 12.82 \approx 13$$

Answer: A-7-6 (13).

Concept: AASHTO Soil Fractions

What type of soil is the fraction passing No. 10 and retained on No. 200 under AASHTO? What type passes No. 200?

$$\text{Passing No. 10 and retained on No. 200} = \text{sand}$$
$$\text{Passing No. 200} = \text{silt and clay}$$

Concept: AASHTO Plasticity

In AASHTO, fine fractions with $PI \ge 11$ are clayey, while fine fractions with $PI \le 10$ are silty. Sizes larger than 75 mm are boulders and cobbles.

$$PI \ge 11 \Rightarrow \text{clayey}$$
$$PI \le 10 \Rightarrow \text{silty}$$

Concept: USCS Coarse and Fine Soils

In USCS, gravelly and sandy soils with less than 50 percent passing No. 200 are coarse-grained soils. Soils with 50 percent or more passing No. 200 are fine-grained soils. The boundary between low and high plasticity is $LL = 50$.

$$F_{200} < 50\% \Rightarrow \text{coarse-grained}$$
$$F_{200} \ge 50\% \Rightarrow \text{fine-grained}$$
$$LL = 50 \Rightarrow \text{low/high plasticity boundary}$$

Concept: USCS Gravel and Sand Fractions

Under USCS, the fraction passing the 76.2 mm sieve and retained on No. 4 is gravel. The fraction passing No. 4 and retained on No. 200 is sand.

$$\text{Passing 76.2 mm and retained on No. 4} = \text{gravel}$$
$$\text{Passing No. 4 and retained on No. 200} = \text{sand}$$

Problem: USCS Soil A

Soil A has 0 percent passing No. 200, 98 percent passing No. 4, $D_{10}=0.5$, $D_{30}=0.9$, and $D_{60}=1.4$. Classify the soil using USCS.

$$F_{200}=0\% < 50\% \Rightarrow \text{coarse-grained}$$
$$\% \text{ passing No. 4}=98\% > 50\% \Rightarrow \text{sand}$$
$$C_u = \frac{1.4}{0.5}=2.8$$
$$C_c = \frac{0.9^2}{0.5(1.4)}=1.16$$

The sand does not satisfy $C_u > 6$, so it is poorly graded.

Answer: SP.

Problem: USCS Soil B

Soil B has 38 percent passing No. 200, 100 percent passing No. 4, liquid limit = 46, and plastic limit = 29. Classify the soil using USCS.

$$F_{200}=38\% < 50\% \Rightarrow \text{coarse-grained}$$
$$\text{Coarse fraction}=100-38=62\%$$
$$\frac{1}{2}(62)=31\%$$
$$\% \text{ passing No. 4}=100\% > 31\% \Rightarrow \text{sand}$$
$$PI=46-29=17>7$$

With more than 12 percent fines and $PI>7$, the soil is clayey sand.

Answer: SC.

Problem: USCS Soil C

Soil C has 68 percent passing No. 200 and 12 percent finer than 0.002 mm. From the distribution, sand is 32 percent, silt is 56 percent, and clay is 12 percent. Classify the soil using USCS.

$$F_{200}=68\% > 50\% \Rightarrow \text{fine-grained}$$
$$\% \text{ silt}=68-12=56\%$$

The dominant fine fraction is silt.

Answer: M, silt.

Problem: USCS Percent Gravel, Sand, and Fines

Using USCS, a sample has 90 percent passing No. 4 and 4 percent passing No. 200. Determine the percentage of gravel, sand, and fines.

$$\% \text{ gravel}=100-90=10\%$$
$$\% \text{ sand}=90-4=86\%$$
$$\% \text{ fines}=4\%$$

Check: $10+86+4=100\%$.

Problem: Corrected USDA Percentages

A soil has sand = 12 percent, silt = 24 percent, and clay = 44 percent. If it contains 20 percent particles larger than 2 mm, the actual sum of sand, silt, and clay is 80 percent. Compute the corrected sand, silt, and clay percentages.

$$\% \text{ corrected sand}=\frac{12}{80}(100)=15\%$$
$$\% \text{ corrected silt}=\frac{24}{80}(100)=30\%$$
$$\% \text{ corrected clay}=\frac{44}{80}(100)=55\%$$

Answer: The soil plots as clay in the USDA system.

Concept: USCS Plasticity Chart and the A-Line

For fine-grained soils in the USCS, classification depends on both the liquid limit and the plasticity index. The A-line separates clays from silts and organic soils.

$$\text{A-line: } PI = 0.73(LL-20)$$

Soils that plot above the A-line with $PI > 7$ are classified as clays (C). Soils below the A-line or with $PI < 4$ are silts or organic soils (M or O). The boundary between low-plasticity (L) and high-plasticity (H) groups is at $LL = 50$ percent. A soil with $LL < 50$ and plotting above the A-line with $PI > 7$ is CL. The same location but with $LL > 50$ is CH. Soils near the boundary band between 4 and 7 plasticity index are dual-symbol, such as CL-ML.

Problem: USCS Classification of Gravel with Gradation Data

A soil has 8 percent passing the No. 200 sieve, 15 percent passing the No. 4 sieve, and gradation coefficients $C_u = 8$ and $C_c = 2.1$. Classify this soil using USCS.

$$F_{200}=8\% < 50\% \Rightarrow \text{coarse-grained}$$
$$\%\text{ retained on No. 4}=100-15=85\% > 50\% \Rightarrow \text{more than half coarse fraction is gravel}$$

Because $F_{200} < 5\%$, use gradation coefficients to subclassify the gravel:

$$C_u=8\ge4 \quad \text{and} \quad C_c=2.1 \in [1,3] \Rightarrow \text{well-graded gravel GW}$$

Answer: GW, well-graded gravel.

Problem: USCS Classification Using the A-Line

A soil has 72 percent passing the No. 200 sieve, a liquid limit of 42 percent, and a plastic limit of 22 percent. Classify the soil using USCS.

$$F_{200}=72\% > 50\% \Rightarrow \text{fine-grained}$$
$$PI=42-22=20$$
$$\text{A-line: } PI=0.73(LL-20)=0.73(42-20)=16.06$$

Since $PI=20 > 16.06$, the soil plots above the A-line and is a clay. Since $LL=42 < 50$, it is low plasticity.

Answer: CL, lean clay.

Problem: AASHTO Group Index Calculation

A subgrade soil has 62 percent passing the No. 200 sieve, a liquid limit of 48 percent, and a plasticity index of 22. Compute the group index and comment on the soil quality as a subgrade material.

$$GI = (F_{200}-35)[0.2+0.005(LL-40)]+0.01(F_{200}-15)(PI-10)$$
$$GI_{LL}=(62-35)[0.2+0.005(48-40)]=27[0.2+0.04]=27(0.24)=6.48$$
$$GI_{PI}=0.01(62-15)(22-10)=0.01(47)(12)=5.64$$
$$GI=6.48+5.64=12.12\approx12$$

A group index of 12 indicates a poor subgrade material. Typical classification is A-7-6 (highly plastic clay). Higher group index means poorer performance as a subgrade.

Answer: $GI = 12$; the soil is a poor subgrade material.

Problem: USCS Classification of Sandy Soil with Fines and Atterberg Data

A soil has 55 percent passing the No. 4 sieve, 20 percent passing the No. 200 sieve, a liquid limit of 35 percent, and a plasticity index of 12. Classify this soil using USCS.

$$F_{200}=20\% < 50\% \Rightarrow \text{coarse-grained}$$
$$\%\text{ passing No. 4}=55\% > 50\% \Rightarrow \text{sand (more than half coarse fraction passes No. 4)}$$

With $F_{200}=20\% > 12\%$, classification is based on Atterberg limits of the fines.

$$\text{A-line check: } PI=0.73(35-20)=10.95 < 12$$

The soil plots above the A-line with $PI = 12 > 7$, so the fines are clayey.

Answer: SC, clayey sand.

Problem: AASHTO Classification of Silty Clay Subgrade

A highway subgrade soil has 80 percent passing No. 200, a liquid limit of 55 percent, and a plastic limit of 30 percent. Determine whether the soil is granular or silt-clay material, compute the plasticity index, and find the group index.

$$F_{200}=80\% > 35\% \Rightarrow \text{silt-clay material}$$
$$PI=55-30=25>11 \Rightarrow \text{clayey fine fraction, group A-7}$$
$$GI_{LL}=(80-35)[0.2+0.005(55-40)]=45[0.2+0.075]=45(0.275)=12.375$$
$$GI_{PI}=0.01(80-15)(25-10)=0.01(65)(15)=9.75$$
$$GI=12.375+9.75=22.125\approx22$$

Since $LL-30=55-30=25=PI$, this is A-7-5. A group index of 22 represents very poor subgrade.

Answer: Silt-clay material, $PI=25$, $GI=22$; classified as A-7-5, very poor subgrade.

Exam Generator Problems

Additional board-style practice items for this topic.

Question Bank: t48

HGE - Geotechnical Engineering / Soil Classification / Civil Engineering Refresher

Soil fraction passing 76.2 mm sieve and retained on No. 4 sieve (4.75 mm) is classified as:

  1. Percent of gravel
  2. Percent of sand
  3. Percent of silt
  4. Percent of clay
Particles between 4.75 mm (No. 4) and 76.2 mm fall in the gravel size range.
$\boxed{\text{Percent of gravel}}$

Question Bank: t49

HGE - Geotechnical Engineering / Soil Classification / Civil Engineering Refresher

Soil fraction passing No. 4 sieve and retained on No. 200 sieve (0.075 mm) is classified as:

  1. Percent of sand
  2. Percent of gravel
  3. Percent of silt
  4. Fine fraction
Particles between 0.075 mm (No. 200) and 4.75 mm (No. 4) are sand-sized.
$\boxed{\text{Percent of sand}}$

Question Bank: t50

HGE - Geotechnical Engineering / Soil Classification / Civil Engineering Refresher

Soil fraction finer than the No. 200 sieve (finer than 0.075 mm) is classified as:

  1. Percent of silt and clay
  2. Percent of sand
  3. Percent of gravel
  4. Coarse fraction
Material finer than the No. 200 sieve ($< 0.075$ mm) consists of fines.
$\boxed{\text{Percent of silt and clay}}$

Question Bank: t51

HGE - Geotechnical Engineering / Soil Classification / Civil Engineering Refresher

The total percentage of a soil sample that passes through the No. 200 sieve is called the:

  1. Fine fraction
  2. Silt fraction
  3. Clay fraction
  4. Sieve residue
Everything passing the No. 200 sieve (silt + clay) is collectively termed the fine fraction $F_{200}$.
$\boxed{\text{Fine fraction}}$

Question Bank: t52

HGE - Geotechnical Engineering / Soil Classification / Civil Engineering Refresher

AASHTO classification: F200 = 86, LL = 70, PI = 32.

Compute the Group Index (GI) and round to the nearest integer.

  1. 33
  2. 18
  3. 16
  4. 35

For the AASHTO data in Question 76, compute the partial group index determined from the liquid limit.

  1. 17.85
  2. 15.62
  3. 33.47
  4. 18.00

For the AASHTO data in Question 76, compute the partial group index determined from the plasticity index.

  1. 15.62
  2. 17.85
  3. 33.47
  4. 15.00

Part 1.

$GI = (F-35)[0.2+0.005(LL-40)] + 0.01(F-15)(PI-10)$
$= (86-35)[0.2+0.005(30)] + 0.01(86-15)(22)$
$= 51(0.35) + 0.01(71)(22) = 17.85 + 15.62 = 33.47$
$\boxed{\approx 33}$

Part 2.

Partial GI (LL term) $= (F-35)[0.2+0.005(LL-40)] = 51[0.2+0.005(30)] = 51(0.35)$
$\boxed{= 17.85}$

Part 3.

Partial GI (PI term) $= 0.01(F-15)(PI-10) = 0.01(71)(22)$
$\boxed{= 15.62}$

Question Bank: v72

HGE - Geotechnical Engineering / Soil Classification / HGE November 2019

According to the Unified Soil Classification System, particles larger than 75 mm are called:

  1. Rock
  2. Gravel
  3. Boulder
  4. Cobble

Cobbles. In the Unified Soil Classification System, particles larger than 75 mm (up to about 300 mm) are cobbles; gravel spans 4.75 mm to 75 mm.

Question Bank: v130

HGE - Geotechnical Engineering / Soil Classification / HGE May 2022

What phenomenon occurs when a cohesionless saturated or partially saturated soil substantially loses strength and stiffness under sudden stress changes, such as earthquake shaking, and temporarily behaves like a liquid?

  1. solidification
  2. landslide
  3. liquefaction
  4. liquidation
The described phenomenon is liquefaction: shaking raises pore-water pressure and reduces effective stress, causing a temporary loss of shear strength and stiffness.

Question Bank: v132

HGE - Geotechnical Engineering / Soil Classification / HGE May 2022

A cohesive soil deposit is considered soft if its unconfined compression strength lies within which range?

  1. 0 to 24 kPa
  2. 48 to 96 kPa
  3. 96 to 192 kPa
  4. 24 to 48 kPa
The standard consistency classification for clay identifies soft clay with an unconfined compression strength of 24 to 48 kPa.

Question Bank: v287

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Formula-mode item rendered with fixed values for lecture/PDF export.

A soil has liquid limit 65, plastic limit 31, natural water content 19, and 19% clay-size particles.

Find liquidity index.

  1. -0.353
  2. -0.276
  3. -0.401
  4. -0.445

Find consistency index.

  1. 1.353
  2. 1.057
  3. 1.538
  4. 1.706

Find activity.

  1. 1.789
  2. 1.398
  3. 2.035
  4. 2.257
Use the standard Atterberg-limit indices.
Computed answers: -0.352941176471, 1.35294117647, 1.78947368421.

Question Bank: v310

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Which index gauges clay swelling potential relative to clay fraction?

  1. Plasticity index
  2. Liquidity index
  3. Consistency index
  4. Activity
Activity is PI divided by clay fraction.

Question Bank: v342

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Formula-mode item rendered with fixed values for lecture/PDF export.

A grain-size curve gives D10=0.16 mm, D30=0.7 mm, D60=2.2 mm and fines content 6%.

Find coefficient of uniformity.

  1. 13.75
  2. 10.74
  3. 15.63
  4. 17.34

Find coefficient of curvature.

  1. 1.39
  2. 1.09
  3. 1.58
  4. 1.76

Return 1 for well-graded sand and 2 otherwise.

  1. Class code 2
  2. Class code 12
  3. Class code 22
  4. Class code 32
Compute Cu and Cc and apply USCS gradation criteria.
Computed answers: 13.75, 1.39204545455, 2.

Question Bank: v346

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Which SPT N range corresponds to the referenced dense/stiff cohesive soil?

  1. 0-4
  2. 10-30
  3. 30-50
  4. 4-10
The source classification uses 30-50 blows.

Question Bank: v347

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Which SPT N range commonly describes loose cohesionless soil?

  1. 0-4
  2. 10-30
  3. 30-50
  4. 4-10
Loose sand commonly has N=4-10.

Question Bank: v348

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Which SPT N range commonly describes very loose cohesionless soil?

  1. 0-4
  2. 10-30
  3. 30-50
  4. 4-10
Very loose sand has N below about 4.

Question Bank: v349

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

USCS particles passing 75 mm but retained on 4.75 mm are what?

  1. Cobbles
  2. Gravel
  3. Boulders
  4. Sand
That range is gravel.

Question Bank: v350

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Particles larger than 75 mm are represented by which listed term?

  1. Cobbles
  2. Boulder only
  3. Gravel
  4. Sand
Cobbles occupy the range immediately above 75 mm.

Question Bank: v351

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Which test determines granular particle-size distribution?

  1. Consolidation
  2. SPT
  3. Unconfined compression
  4. Sieve analysis
Sieve analysis separates grains by size.

Question Bank: v374

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

What is the nominal No. 200 sieve opening?

  1. 0.020 mm
  2. 0.064 mm
  3. 0.074 mm
  4. 0.0054 mm
It is approximately 0.075 mm.

Question Bank: v378

HGE - Geotechnical Engineering / Soil Classification / HGE Refresher Series

Formula-mode item rendered with fixed values for lecture/PDF export.

A soil contains 14% sand, 32% silt, and the remainder clay.

Find modified sand percentage.

  1. 17.72 %
  2. 13.84 %
  3. 20.15 %
  4. 22.35 %

Find modified silt percentage.

  1. 40.51 %
  2. 31.64 %
  3. 46.06 %
  4. 51.08 %

Find modified clay percentage.

  1. 68.35 %
  2. 53.38 %
  3. 77.72 %
  4. 86.19 %
Renormalize the three fractions to the reference total.
Computed answers: 17.7215189873, 40.5063291139, 68.3544303797.