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Biaxial Bending (Purlins)

Concept

Interaction Equation:

$$ \frac{M_{ux}}{\phi_b M_{nx}} + \frac{M_{uy}}{\phi_b M_{ny}} \leq 1.0 $$
$$ \frac{M_{ax}}{M_{nx}/\Omega_b} + \frac{M_{ay}}{M_{ny}/\Omega_b} \leq 1.0 \quad \text{(ASD)} $$

Where:

Note: When lateral loads applied to the top flange of the beam do not pass through the centroid of the section, reduce the plastic/elastic section modulus for the y-axis by 50%.

Purlin Load Components

For a roof slope angle $\theta$, resolve the gravity load into components normal and parallel to the roof plane.

$$ w_x=w\cos\theta, \qquad w_y=w\sin\theta $$ $$ M_x=\frac{w_xL^2}{8} \quad \text{for a simple-span purlin} $$

Weak-Axis Bending Strength

506.6 I-Shaped Members and Channels Bent about their Minor Axis

The nominal flexural strength, $M_n$, is the lower value obtained according to the limit states of yielding (plastic moment) and flange local buckling.

506.6.1 Yielding

$$ M_n = M_p = F_y Z_y \leq 1.6 F_y S_y $$

506.6.2 Flange Local Buckling

1. For sections with compact flanges, the limit state of yielding shall apply.

2. For sections with non-compact flanges:

$$ M_n = \left[ M_p - (M_p - 0.7 F_y S_y) \left( \frac{\lambda - \lambda_{pf}}{\lambda_{rf} - \lambda_{pf}} \right) \right] $$

Moment Diagram for Purlins with Sag Rod at the Midspan

$$ M_y=\frac{w_yL^2}{32} \quad \text{for one sag rod at midspan} $$
Concept

Moment Diagram for Purlins with Sag Rod at Third Points

$$ M_y=\frac{w_yL^2}{72} \quad \text{for sag rods at third points} $$
Concept Concept Concept Concept Concept Concept Concept
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Exam Generator Problems

Additional board-style practice items for this topic.

Question Bank: q16

PSAD - Steel Design / Purlins / Engr. Janclyde Espinosa (Clidez)

CE Board November 2010
Light-grade steel channel was used as a purlin of a truss. The top chord of the truss is inclined 1V:3H and distance between trusses is equal to 3m. The purlin has a weight of 71N/m and spaced at 1.2m on centers. The dead load including the roof materials is 1200Pa, live load is 1000Pa and wind load is 1440Pa. Coefficient of pressure at leeward and windward are 0.6 and 0.2, respectively.
Sag rods are placed at the middle thirds and Fbx=Fby=138MPa.
Use:
Sx=4.48x10⁴mm³
Sy=1.18x10⁴mm³
Using the interaction formula, determine the following:

Maximum ratio of actual to allowable bending stress for combination of (D+L) load.

  1. 0.469
  2. 0.438
  3. 0.496
  4. 0.483

Maximum ratio of actual to allowable bending stress for combination of 0.75(D+L+W)--windward side.

  1. 0.393
  2. 0.327
  3. 0.286
  4. 0.295

Maximum ratio of actual to allowable bending stress for combination of (D+L) if one line of sag rod was placed at the midspan.

  1. 0.616
  2. 0.514
  3. 0.723
  4. 0.567

Solution pending in psadquestions/q16.json.